I’ve just seen your post here: Resume previously planned solution? - #21 by roganjosh which frames this current question better for me.
…would be able to know that Vehicle 1 is closer and also that it can also be assigned to the service.
Bold highlight mine. It’s a combinatorial problem; you cannot know unless you try. What you’re trying here is a greedy approach - you can do that without Jsprit. I’m not sold on your approach. I’d be surprised if the other conversation goes into any further specifics, unfortunately; this would cost people their jobs because it’s mostly unsolved regardless of libraries and academia, but worth a lot to companies…